Algebra 2 by Richard Wright

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4-04 Find Rational Zeros of Polynomial Functions (4.5)

Mr. Wright teaches the lesson.

Objectives:

SDA NAD Content Standards (2018): AII.4.3, AII.5.1, AII.5.3, AII.6.3

stepping stones
Figure 1: Stepping stones. (pxfuel.com)

A landscape company is going to put some decorative rectangular prism-shaped stepping stones to make a path across a creek. Each stone will use 648 cubic inches of cement because that is convenient based on their cement supply. They decided that having the width be six inches greater than the length is a pleasing proportion and that the height should be one fourth the width for strength. What should be the dimensions of the stepping stone?

This problem can be solved by writing a cubic function and solving a cubic equation for the volume of the stepping stone. This lesson highlights a variety of tools for writing polynomial functions and solving polynomial equations.

Evaluating a Polynomial Using the Remainder Theorem

The Remainder Theorem provides a convenient way to evaluate polynomials based on division. A polynomial may be evaluated at f(k) by dividing it by xk. In other words, f(k) is the remainder obtained by dividing f(x) by xk. Synthetic division makes the process quick.

The Remainder Theorem

If a polynomial f(x) is divided by xk, then the remainder is the value f(k).

Use the Remainder Theorem to Evaluate a Polynomial

To evaluate polynomial f(x) at x = k using the Remainder Theorem,

  1. Use synthetic division to divide the polynomial by xk.
  2. The remainder is the value f(k).

Example 1: Using the Remainder Theorem to Evaluate a Polynomial

Use the Remainder Theorem to evaluate f(x) = x4 − 3x3x2 + 2x − 13 at x = 2.

Solution

To use the Remainder Theorem, use synthetic division to divide the polynomial by x − 2.

$$ \begin{array}{rrrrrr} \underline{2}| & 1 & -3 & -1 & 2 & -13 \\ & & 2 & -2 & -6 & -8\\ \hline & 1 & -1 & -3 & -4 & |\underline{-21} \end{array} $$

The remainder is −21. Therefore, f(2) = −21.

Analysis

It is possible to check the answer by evaluating f(2).

f(x) = x4 − 3x3x2 + 2x − 13

f(2) = (2)4 − 3(2)3 − (2)2 + 2(2) − 13

= −21

Try It 1

Use the Remainder Theorem to evaluate f(x) = 3x5x4 − 2x3 + x2 + 3 at x = 1.

Solution

f(1) = 4

Using the Factor Theorem to Solve a Polynomial Equation

The Factor Theorem says that if (xk) is a factor of a function, then x = k is a zero of the function. A zero is a value of x that makes f(x) = 0.

It turn out that a polynomial of degree n in the complex number system will have n zeros. The Factor Theorem can be used to completely factor a polynomial into the product of n factors. Once the polynomial has been completely factored, its zeros can easily be found.

The Factor Theorem

According to the Factor Theorem, k is a zero of f(x) if and only if (xk) is a factor of f(x).

Use the Factor Theorem to Solve a Polynomial Equation

To solve a polynomial equation given one factor using the factor theorem,

  1. Use synthetic division to divide the polynomial by the given factor, (xk).
  2. Confirm that the remainder is 0.
  3. If the quotient is NOT a quadratic, repeat steps 1 and 2 with another factor using the quotient as the polynomial.
  4. If the quotient IS a quadratic, factor the quadratic quotient if possible.
  5. Set each factor equal to zero and solve for x.

Example 2: Use the Factor Theorem to Solve a Polynomial Equation

Show that (x − 1) is a factor of x3 − 2x2 − 5x + 6. Find the remaining factors. Use the factors to determine the zeros of the polynomial.

Solution

Use synthetic division to show that (x − 1) is a factor of the polynomial.

$$ \begin{array}{rrrrr} \underline{1}| & 1 & -2 & -5 & 6 \\ & & 1 & -1 & -6 \\ \hline & 1 & -1 & -6 & |\underline{\phantom{0}0} \end{array} $$

The remainder is zero, so (x − 1) is a factor of the polynomial. The quotient is x2x − 6 which is a quadratic. Factor that quadratic.

x2x − 6 = (x + 2)(x − 3)

Set each factor, including the given one, equal to zero and solve for x.

x − 1 = 0

x = 1

Or

x + 2 = 0

x = −2

Or

x − 3 = 0

x = 3

The zeros of x3 − 2x2 − 5x + 6 are −2, 1, and 3.

Try It 2

Use the Factor Theorem to find the zeros of f(x) = x3 − 5x2 − 10x + 24 given that (x − 4) is a factor of the polynomial.

Answer

The zeros are −2, 3, and 4.

Practice Problems

    Use the remainder theorem to evaluate f(x) at the given x value.

  1. f(x) = x2 + 5x − 15; x = 3
  2. f(x) = 2x3 − 2x2 + x + 1; x = −2
  3. f(x) = 3x3 − 4x2 − 15; x = 3
  4. f(x) = 2x3x2 − 3x − 10; x = 5
  5. f(x) = 4x3 − 2x + 9; x = −1
  6. Show that the given binomial is a factor of f(x), then find the zeros of f(x).

  7. f(x) = x3 + 6x2 + 5x − 12; (x + 4)
  8. f(x) = x3 − 19x − 30; (x + 2)
  9. f(x) = 2x3 − 3x2 − 32x − 15; (x + 3)
  10. f(x) = 2x4x3 − 9x2 + 4x + 4; (x − 2), (x − 1)
  11. f(x) = 3x4 + 2x3 − 13x2 − 8x + 4; (x + 1), (x + 2)
  12. Mixed Review

  13. (4-03) Simplify (2x3 + 3x2 − 4x + 5) ÷ (x2 + x − 4)
  14. (4-03) Simplify (3x5 − 5x3x + 4) ÷ (x − 2)
  15. Solve by factoring.

  16. (4-02) 2x2 + 9x + 4 = 0
  17. (4-02) 2x3 + 2x2 = 24x
  18. (4-02) x3 + 2x2 − 16x − 32 = 0

Answers

  1. 9
  2. −25
  3. 30
  4. 200
  5. 7
  6. −4, −3, 1
  7. −3, −2, 5
  8. −3, −1/2, 5
  9. −2, −1/2, 1, 2
  10. −2, −1, 1/3, 2
  11. 2x + 1 + \(\frac{3x + 9}{x^2 + x - 4}\)
  12. 3x4 + 6x3 + 7x2 + 14x + 27 + \(\frac{58}{x-2}\)
  13. −4, −1/2
  14. −4, 0, 3
  15. −4, −2, 4